[{"data":1,"prerenderedAt":47},["ShallowReactive",2],{"q-sw-106-2-research-methods-020":3},{"subject":4,"subjectSlug":5,"subjectFullName":4,"question":6,"related":24},"社會工作研究方法","research-methods",{"id":7,"webId":8,"year":9,"session":10,"subject":4,"legacy":11,"number":12,"stem":13,"options":14,"answer":19,"answerNote":20,"images":21,"lawTimestamp":9,"explanation":22,"freq":23},"sw-106-2-社會工作研究方法-020","sw-106-2-research-methods-020",106,2,false,20,"自變項與依變項皆為類別變項時，欲檢定兩變項的獨立性時我們會採用卡方檢定。今若進行交叉分析的自變項有 2 個屬性、依變項有 4 個屬性，試問卡方檢定之自由度為多少？",{"A":15,"B":16,"C":17,"D":18},"8","6","3","2","C",null,[],"本題考點是卡方獨立性檢定自由度的計算。依卡方檢定公式,交叉表的自由度=(列數−1)×(行數−1);本題自變項有 2 個屬性、依變項有 4 個屬性,構成 2×4 交叉表,自由度=(2−1)×(4−1)=1×3=3,故選 C。A 8 是誤將 2 與 4 直接相乘,忘了各減 1;B 6 是只有一邊減 1 的誤算(如 2×3);D 2 亦不符(列−1)×(行−1)的公式結果。記住「行列各減一再相乘」即可,屬性數本身不是自由度。",1,[25,28,31,35,39,43],{"webId":26,"stem":27,"number":23,"year":9,"session":23},"sw-106-1-research-methods-001","什麼是社會工作研究的第一步？",{"webId":29,"stem":30,"number":10,"year":9,"session":23},"sw-106-1-research-methods-002","執行研究是為了解概念，但我們仍得在研究前，針對概念給予基本描述與簡要定義。請問這個步驟是：",{"webId":32,"stem":33,"number":34,"year":9,"session":23},"sw-106-1-research-methods-003","皮爾森相關係數（r）有幾個特色，下列敘述何者錯誤？",3,{"webId":36,"stem":37,"number":38,"year":9,"session":23},"sw-106-1-research-methods-004","關於信效度的說明，下列何者正確？",4,{"webId":40,"stem":41,"number":42,"year":9,"session":23},"sw-106-1-research-methods-005","當我們要判斷兩個變項間是否有因果關係時，下列那種判斷標準不合適？",5,{"webId":44,"stem":45,"number":46,"year":9,"session":23},"sw-106-1-research-methods-006","關於演繹法的說明，何者有誤？",6,1784109472187]